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7k^2-29k+8=0
a = 7; b = -29; c = +8;
Δ = b2-4ac
Δ = -292-4·7·8
Δ = 617
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{617}}{2*7}=\frac{29-\sqrt{617}}{14} $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{617}}{2*7}=\frac{29+\sqrt{617}}{14} $
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